Luas permukaanya adalah?
Jawab:
Penjelasan dengan langkah-langkah:
[tex]t = 9, c = 24, d = 5\\\\t = 9 = a\sin(\alpha), c' = \dfrac{24}{2}\sqrt{2} = a\cos(\alpha)\\\\a^2 = 9^2+12^2\cdot 2\\\\a = \sqrt{369}=3\sqrt{41}=b[/tex]
[tex]LP_1 = 4\cdot \sqrt{s(s-a)(s-b)(s-c)}\to a = b=3\sqrt{41}, c = 24\\\\LP_1 = 4\cdot |s-3\sqrt{41}|\sqrt{s(s-24)}\to s = \dfrac{a+b+c}{2}=3\sqrt{41}+12=3(4+\sqrt{41})\\\\LP_1 = 4^2\cdot 3^2\sqrt{(\sqrt{41}+4)(\sqrt{41}-4)} = 144\cdot \sqrt{41-16}\\\\LP_1 = 144\cdot 5 = 720[/tex]
[tex]LP_2 = 4\cdot 24\cdot 5 = 480\\\\LP_{total} = LP_1+LP_2\\\\LP_{total} = 720+480\\\\\Huge{\boxed{\boxed{\boldsymbol{LP_{total} = 1200 \; cm^2}}}}[/tex]
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